Answer:
D. A, A, J, A, A, K
Step-by-step explanation:
It is given that it is highly likely that Malika will randomly select the letter A from a group. This means, there is a very high probability of selecting the letter A from the group. So, for all the given options we have to find what is the probability of randomly selecting the letter A.
Option A:
Total letters = Total Possible Outcomes = 5
Occurrence of A = Total Favorable Outcomes = 1
Since, probability is equal to Total Favorable Outcomes divided by Total Possible outcomes, the probability of selecting A in this case would be = [tex]\frac{1}{5}[/tex] = 0.2
Option B:
Total letters = Total Possible Outcomes = 5
Occurrence of A = Total Favorable Outcomes = 2
The probability of selecting A in this case would be = [tex]\frac{2}{5}[/tex] = 0.4
Option C:
Total letters = Total Possible Outcomes = 6
Occurrence of A = Total Favorable Outcomes = 3
The probability of selecting A in this case would be = [tex]\frac{3}{6}[/tex] = 0.5
Option D:
Total letters = Total Possible Outcomes = 6
Occurrence of A = Total Favorable Outcomes = 4
The probability of selecting A in this case would be = [tex]\frac{4}{6}[/tex] = 0.67
Hence, from option D, we have the highest probability of selecting the letter A from given letters.
Therefore, Malika would be selecting from the group in option D. A, A, J, A, A, K
