Respuesta :
1) for the coin A its value to first year , is
a1 = 25+25(7/100)= 25[1+7/100]
the second year a2 = a1 + 7/100 a1
a2 = 25+25(7/100) + [25+25(7/100)]7/100
a2= 25+25(7/100) + 25(7/100) + 25(7/100)^2
a2=25[1+7/100]^2
in t years will be at = 25[1+7/100]^t =25[1+0,07]^t
for the coin B IS THE SAME PROCEDURE
bt = 40[1+0,05]^t
Answer: For coin A,
[tex]v=25(1.07)^t[/tex]
For coin B,
[tex]v=40(1.05)^t[/tex]
Step-by-step explanation:
The exponential equation is,
[tex]y=ab^x[/tex]
Where, a is the initial value,
b is the growth or decay factor,
Since, Coin A worth $25 and increase by 7% each year,
So, the coin A's value after t years,
[tex]v=25(1+\frac{7}{100})^t[/tex]
[tex]v=25(1+0.07)^t[/tex]
[tex]\implies v=25(1.07)^t[/tex]
Which is the required equation for coin A.
Now, Coin B worth $40 increase by 5% each year,
So, the coin B's value after t years,
[tex]v=40(1+\frac{5}{100})^t[/tex]
[tex]v=40(1+0.05)^t[/tex]
[tex]\implies v=40(1.05)^t[/tex]
Which is the required equation for coin B.