Respuesta :
the point, M, that divides segment AB into a ratio of 3:1
A is at (-4, -2) and B is at (4, -10).
Apply section formula
[tex](\frac{mx_2 + nx_1}{m+n} , \frac{my_2 + ny_1}{m+n})[/tex]
Here m,n is the ratio
m =3, n= 1
A is (-4,-2) that is (x1,y1)
B is at (4, -10) that is (x2,y2)
plug in all the values in the formula
[tex](\frac{3(4) + 1(-4)}{3+1} ,\frac{3(-10) + 1(-2)}{3+1})[/tex]
[tex](\frac{8}{4} ,\frac{-32}{4})[/tex]
(2, -8)
Point M is (2,-9)
