We know that According to Law of Sines :
[tex]\clubsuit[/tex] [tex]\frac{SinA}{a} = \frac{SinB}{b} = \frac{SinC}{c}[/tex]
Where A - B - C are Angles of the Triangle and a - b - c are Opposite Sides corresponding to those Angles A - B - C
We need to find the length of Path-2 whose Opposite Angle is 45°
We need to find the Angle Opposite to 300 m length to solve the problem
Angle Opposite to 300 m Length = 180° - (45° + 105°) = 30°
⇒ [tex]\frac{Sin45}{Length\;of\;Path-2} = \frac{Sin30}{300}[/tex]
⇒ [tex]\frac{1}{\sqrt{2}(Length\;of\;Path-2)} = \frac{1}{600}[/tex]
⇒ [tex]Length\;of\;Path-2 = \frac{600}{\sqrt{2}} = 424\;m[/tex]
Option D is the Answer
