Respuesta :

[tex]\left( \dfrac{1}{64} \right)^{-2x+6} = \left(\dfrac{1}{16} \right)^{8x-5}\\\left( \dfrac{1}{64} \right)^{-2x}\left( \dfrac{1}{64} \right)^6 = \left(\dfrac{1}{16} \right)^{8x}\left( \dfrac{1}{16} \right)^{-5}\\\left( \dfrac{1}{2} \right)^{-12x}\left( \dfrac{1}{2} \right)^{36} = \left( \dfrac{1}{2} \right)^{32x}\left( \dfrac{1}{2} \right)^{-20}\\\left( \dfrac{1}{2} \right)^{56} = \left( \dfrac{1}{2} \right)^{44x}\\56 Ln (1/2) = 44x Ln(1/2)\\x = \dfrac{56}{44} = \dfrac{14}{11}[/tex]