No, because it has a constant rate of change
By looking at this table
The y value changes at a constant multiple of 2
6 4
7 2 (4-2 is a difference of 2)
8 0 (2-0 is a difference of 2)
9 -2 (0-2 is a difference of 2)
This means it is Linear
No, because it has a constant rate of charge.
Rate of change of function: [tex]\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\begin{array}{ccc}6\to4\\7\to2\end{array}\Rightarrow\dfrac{2-4}{7-6}=\dfrac{-2}{1}=-2\\\\\begin{array}{ccc}7\to2\\8\to0\end{array}\Rightarrow\dfrac{0-2}{8-7}=\dfrac{-2}{1}=-2\\\\\begin{array}{ccc}8\to0\\9\to-2\end{array}\Rightarrow\dfrac{-2-0}{9-8}=\dfrac{-2}{1}=-2\\\\[/tex]
