let's take a peek at the line and let's use two points from it, hmmmm it passes through (0, 8) and hmm (4, -4), so
[tex]\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-4}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-4-8}{4-0}\implies \cfrac{-12}{4}\implies -3[/tex]
Answer:
slope = -3
Step-by-step explanation:
To find out slope, pick two points from the line
(0,8) and (2,2)
Slope formula =[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
(0,8) is (x1,y1)
(2,2) is (x2,y2)
Plug in all the values in the formula
Slope=[tex]\frac{2-8}{2-0}[/tex]
= [tex]\frac{-6}{2} =-3[/tex]
The slope of the given line is -3
