2.7 + 1.7i
We require the fractions to have a common denominator.
multiply the numerator of the first fraction by (3 - i) and the numerator of the second fraction by (3 + 1)
= [tex]\frac{3i(3-i)+8(3+i)}{(3+i)(3-i)}[/tex]
= [tex]\frac{9i-3i^2+24+8i}{9-i^2}[/tex]
[ note that i² = ([tex]\sqrt{(-1)^2}[/tex] = - 1]
= [tex]\frac{17i+27}{10}[/tex] = 2.7 + 1.7i ← in standard form
