Respuesta :
Answer:
(a) [tex]6d+20b=150[/tex]
(b) [tex]d=\frac{150-20b}{6}[/tex]
(c) [tex]b=\frac{150-6d}{20}[/tex]
Step-by-step explanation:
We have been given that Marcy has $150 to buy packages of hot dogs (d) and hamburgers (b) for her booth at the carnival.
(a) We have been given that the cost for one package of hot dogs is $6, so the cost for d packages of hot dogs will be 6*d.
We are also told that cost for one package of hamburgers is $20, therefore, cost for b packages of hamburgers will be 20*b.
To write an equation that can be used to find the possible combination of hot dog and hamburger packages Marcy can buy using her budget of exactly $150, we will equate the sum of 6*d and 20*b with 150.
[tex]6d+20b=150[/tex]
Therefore, our desired equation will be [tex]6d+20b=150[/tex].
(b) We will solve for one unknown in terms of other unknown. We can solve our equation for d in terms of b by separating d to one side of our equation.
First of all we will subtract 20*b from both sides of our equation.
[tex]6d+20b-20b=150-20b[/tex]
[tex]6d=150-20b[/tex]
Now we will divide both sides of our equation by 6.
[tex]\frac{6d}{6}=\frac{(150-20b)}{6}[/tex]
[tex]d=\frac{(150-20b)}{6}[/tex]
Therefore, we can write the value of d as: [tex]d=\frac{(150-20b)}{6}[/tex].
(c) We will solve for one unknown in terms of other unknown. We can solve our equation for b in terms of d by separating b to one side of our equation.
First of all we will subtract 6*d from both sides of our equation.
[tex]6d-6d+20b=150-6d[/tex]
[tex]20b=150-6d[/tex]
Now we will divide both sides of our equation by 20.
[tex]\frac{20b}{20}=\frac{(150-6d)}{20}[/tex]
[tex]b=\frac{150-6d}{20}[/tex]
Therefore, we can write the value of d as: [tex]b=\frac{(150-6d)}{20}[/tex].
