Hello from MrBillDoesMath!
Answer:
k-2 is not a factor of k^3-k^2-k-1.
Discussion:
I think you are asking if k-2 is a factor of (k^3-k^2-k-1). If it were, then substituting k = 2 in the polynomial would yield 0. Let's check:
2^3 - 2^2 - 2 - 1 = "k^3-k^2-k-1"
8 - 4- 2- 1 = 1 <> 0.
So k-2 is not a factor of k^3-k^2-k-1.
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
Answer:
No, K-2 is not a factor of (k^3-k^2-k-1)\(k-2).
Step-by-step explanation:
