What is the error due to using linear interpolation to estimate the value of sinxsin⁑x at x = \pi/3? your answer should have at least three significant figures, accurate to within 0.1%. (e.g., 1.23 and 3.33e-8 both have three significant figures.)?

Respuesta :

Answer:

  • using y = x, the error is about 0.1812
  • using y = (x -Ο€/4 +1)/√2, the error is about 0.02620

Step-by-step explanation:

The actual value of sin(Ο€/3) is (√3)/2 β‰ˆ 0.86602540.

If the sine function is approximated by y=x (no error at x = 0), then the error at x=Ο€/3 is ...

... x -sin(x) @ x=Ο€/3

... Ο€/3 -(√3)/2 β‰ˆ 0.18117215 β‰ˆ 0.1812

You know right away this is a bad approximation, because the approximate value is Ο€/3 β‰ˆ 1.04719755, a value greater than 1. The range of the sine function is [-1, 1] so there will be no values greater than 1.

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If the sine function is approximated by y=(x+1-Ο€/4)/√2 (no error at x=Ο€/4), then the error at x=Ο€/3 is ...

... (x+1-Ο€/4)/√2 -sin(x) @ x=Ο€/3

... (Ο€/12 +1)/√2 -(√3)/2 β‰ˆ 0.026201500 β‰ˆ 0.02620

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