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Problem 3 among the cast aluminum parts manufactured on a certain day, 80% were flawless, 15% had only minor flaws, and 5% had major flaws. find the probability that a randomly chosen part

a.has a flaw (major and minor).

b.has no major flaws.

Respuesta :

charlief22

Greetings!

Answer:

A) P(flaw) = 0.2

B) P(No major flaws) = 0.95

Step-by-step explanation:

A)

To find the probability of flaws, we can find the probability of no flaws first by dividing by 100:

P(no flaw) = [tex]\frac{80}{100}[/tex] = 0.8

So then:

P(flaw) = 1 - P(no flaw) = 1 - 0.8 = 0.2

P(flaw) = 0.2

B)

First, we need to find the probability of major flaws:

P(major flaws) = [tex]\frac{5}{100} = 0.05[/tex]

P(Major flaws) = 0.05

So to find the probability of no major flaws:

P(No major flaws) = 1 - P(major flaws) = 1 - 0.05 = 0.95

P(No major flaws) = 0.95


Hope this helps!

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