26. In dilute nitric acid, HNO, copper metal dissolves according to the following equation: How many grams of HNO, are needed to dissolve 11.45 g of Cu according to this equation?
Answer:30.27 g HNO3 Step by step solution: 45 g Cu x 1 mol Cu / 63.54 g Cu = 0.1802 mol Cu 0.1802 mol Cu x 8 mol HNO3/3 mol Cu =0.4805 mol HNO3 Molar Mass HNO3 = 1.0 + 14.0 +3×16.0 = 63.0 g/mol 0.4805 moles HNO3 x 63.0 g HNO3/1 mol HNO3 = 30.27 g HNO3
