Answer:
The number of problems solved = 2000
Step-by-step explanation:
Let us assume the monthly quota of problems be x
number of problem solved in first week = 25 % of x =[tex]0.25x[/tex]
number of problems solved in 2nd week = 110% of (problems solved in 1st week)
= [tex]1.10 (0.25x)[/tex]
=[tex]0.275x[/tex]
number of problem solved 3rd week= 60% of ( problems solved in 1st and 2nd week)
= [tex]0.60(0.25x+0.275x)[/tex]
=[tex]0.60(0.525x)[/tex]
=[tex]0.315x[/tex]
number of problem solved in 4th week = [tex]320[/tex]
now we have
number of problems solved in ll 4 weeks = x
[tex]0.25x +0.275x+0.315x+320=x[/tex]
[tex]0.84x+320=x[/tex]
[tex]320=x-0.84x[/tex]
[tex]320=0.16 x[/tex]
[tex]x=\frac{320}{0.16}[/tex]
[tex]x=2000[/tex]
Hence the number of problems solved = 2000