If lines joined each given point on the graph to the origin, which points would be on lines that represent a unit rate greater than the one represented in the table?

If lines joined each given point on the graph to the origin which points would be on lines that represent a unit rate greater than the one represented in the ta class=

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Answer:

The first three, (2, 8), (3, 9) and (4, 10).

Step-by-step explanation:

The unit rate, or rate of change, is another term for the slope.

The formula for slope is

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex].

The slope in the table would be given by

m = (22-11)/(10-5) = 11/5 = 2.2.

For the slope of the line that goes through (2, 8) and (0, 0), we have

m = (8-0)/(2-0) = 8/2 = 4.  This is greater than 2.2.

For the slope of the line that goes through (3, 9) and (0, 0), we have

m = (9-0)/(3-0) = 9/3 = 3.  This is greater than 2.2.

For the slope of the line that goes through (4, 10) and (0, 0), we have

m = (10-0)/(4-0)/ = 10/4 = 2.5.  This is greater than 2.2.

For the slope of the line that goes through (5, 8) and (0, 0), we have

m = (8-0)/(5-0) = 8/5 = 1.6.  This is not greater than 2.2.

For the slope of the line that goes through (6, 7) and (0, 0), we have

m = (7-0)/(6-0) = 7/6 = 1.16.  this is not greater than 2.2.

For the slope of the line that goes through (7, 6) and (0, 0), we have

m = (6-0)/(7-0) = 6/7 = 0.86.  This is not greater than 2.2.