Respuesta :

gmany

The point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (3, 0) and (6, -3). Substitute:

[tex]m=\dfrac{-3-0}{6-3}=\dfrac{-3}{3}=-1[/tex]

The point-slope form:

[tex]y-(-3)=-1(x-6)\\\\\boxed{y+3=-(x-6)}[/tex]

or

[tex]y-0=-1(x-3)\\\\\boxed{y=-(x-3)}[/tex]

The slope-intercept form:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

From the second point-slope form we have slope-intercept form:

[tex]y=-(x-3)\\\\y=-x-(-3)\\\\\boxed{y=-x+3}[/tex]