The orbital period, P, of the planet's distance from the sun, a, in astronomical units is related by the formula p=a^3/2. If Saturn's orbital periodt n 29.5 years what is its distance from the sun?

Respuesta :

Answer:

Distance of Saturn from sun is 9.5473  astronomical units

Step-by-step explanation:

We have given,

A formula relating the planet's orbital period and planet's distance from the sun. i.e p = [tex]a^{\frac{3}{2} }[/tex]

since we have, orbital period of Saturn = 29.5 years

And we need to find the distance of Saturn from the sun.

so we can use the given formula: p = [tex]a^{\frac{3}{2} }[/tex]

Here, Orbital period , p = 29.5 , Let a be the distance between Saturn and sun.

29.5 = [tex]a^{\frac{3}{2} }[/tex]

Squaring both sides, we get :

29.5² = [tex]a^{3}[/tex]

Taking cube root both sides, we get:

[tex]29.5^{\frac{2}{3} } =a[/tex]

a = 9.5473  astronomical units

Distance of Saturn from sun is 9.5473  astronomical units