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A car traveling due east at 20 m/s reverses its direction over a period of 10 seconds so that it is now traveling due west at 20 m/s. What is the direction of the car’s average acceleration over this period?

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skyluke89

Answer:

west

Explanation:

We can take east as positive (+) direction and west as negative (-) direction. With this sign convention, we have:

- Initial velocity: u = +20 m/s (due east)

- Final velocity: v = -20 m/s (due west)

- Time taken to change velocity: t = 10 s

Therefore, we can use the formula for the acceleration to calculate the car's acceleration:

[tex]a=\frac{v-u}{t}=\frac{(-20 m/s)-(+20 m/s)}{10 s}=\frac{-40 m/s}{10 s}=-4 m/s^2[/tex]

And the negative sign means the direction of the car's acceleration is west.

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