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What is the area of a parallelogram whose vertices are E(−9, -2), F(9, -2), G(1, −7), and H(-17, −7)?

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Answer:

A = 90

Step-by-step explanation:

We need to find the length of the base

Let EF be the base

length = change in x  (since the y's are the same value)

           = (9--9) = (9+9) = 18

Now we need to find the height  (change in y values)

-7 --2

-7 +2 = -5

But the value is positive because we are finding the distance  

height is 5 units

A = bh

A = 18*5

A = 90

Answer:

90

Step-by-step explanation:

 = (9--9)= 18         bc remember when there is two negatives together it becomes a positive.

-7+2 = -5

A = bh         now since our b is 18  and our h is 5 were going to multiply them

A = 18*5

A = 90

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