Find the value of x in the triangle shown below.

Answer:
[tex]D.\hspace{8}x=8[/tex]
Step-by-step explanation:
Use the Pythagorean theorem which states that in every right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs. So, if in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relationship is true:
[tex]c^2=a^2+b^2[/tex]
In this case, let:
[tex]c=10\\\\a=x\\\\b=6[/tex]
Hence:
[tex]10^2=x^2+6^2\\\\100=x^2+36[/tex]
Solving for x:
[tex]x^2=100-36\\\\x^2=64\\\\[/tex]
[tex]\sqrt{x^2} =\sqrt{64}\\\\x=8[/tex]
Therefore, the value of x in the triangle is 8