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WILL MARK AS BRAINLIEST FOR THESE QUESTIONS.

Joe owns a sandwich shop. He charges $10.00 for two sandwiches and one drink and $6.50 for one sandwich and one drink. How much does Joe charge per sandwich? How much per drink?

What is the solution of the system? Use elimination.
3 − 2 = 5
−2 + = −3


Producing a musical costs $8,000 plus $300 per performance. One sold-out performance earns $700
income. If every performance sells out, how many performances are needed to break even?


In a chemistry lab, you have two vinegars. One is 20% acetic acid and one is 50% acetic acid. You want
to make 200 mL of a vinegar with 30% acetic acid. How many milliliters (mL) of each vinegar do you
need to mix together?

Respuesta :

1.

Let the sandwich be represented by = x

Let the drink be represented by = y

As given, Joe charges $10.00 for two sandwiches and one drink, so equation becomes 2x+y=10    ....(i)

He charges $6.50 for one sandwich and one drink, so equation becomes x+y=6.50  ....(ii)

Subtracting (ii) from (i) we get

x=3.50

And as x+y=6.50

y=6.50-3.50=3.00

Hence, cost of a sandwich is $3.50 and a drink is $3.00

2.

the question is incomplete. coordinates are missing

3.

Let x represent the number of performances

cost = 8000+300x

revenue = 700x

To break even, the cost must be equal to the revenue.

[tex]8000+300x=700x[/tex]

[tex]400x=8000[/tex]

so x=20

Hence, 20 performances are needed to break even.

4.

Let us take x for 20% material, y for 50% material

[tex]\frac{20x+50y}{200}=30[/tex]

[tex]20x+50y=6000[/tex]    ......... (1)

Accounting for volumes to use, x+y=200 or x=200-y ................ (2)

Putting the value of x in (1)

[tex]20(200-y)+50y=6000[/tex]

[tex]4000-20y+50y=6000[/tex]

[tex]4000+30y=6000[/tex]

[tex]30y=2000[/tex]

y=66.67

x=200-y = 200-66.67 =133.33

Hence, 133.33 ml of 20% acetic acid and 66.67% of 50% acetic acid is needed.





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