Answer:
The perpendicular distance between the opposite sides of rhombus is 5 units.
Step-by-step explanation:
Given a rhombus has sides 10 cm long and an angle of 30°.
we have to find the distance between opposite two sides of rhombus.
Since side of rhombus is 10 cm and one of the acute angle is of 30° then
In ΔAED,
[tex]sin\angle DAE=\frac{DE}{AD}[/tex]
⇒ [tex]sin30^{\circ}=\frac{DE}{10}[/tex]
⇒ [tex]DE=\frac{1}{2}\times 10=5[/tex]
Hence, the perpendicular distance between the opposite sides of rhombus is 5 cm
