A rectangle’s width is 2 meters shorter than its length, l. Its area is 168 square meters. Which equation can be used to find the length of the rectangle?

Respuesta :

Answer:

Depends on answer choice given.

[tex]l^2-2l-168\\or\\169=(l+1)^2\\or\\ l=12, w=10[/tex]

Step-by-step explanation:

To find the area of a rectangle, use the formula A=l*w. Here the area is 168, the length is l and the w=l-2.

[tex]A=l*w\\168= l*(l-2)\\168=l^2-2l\\0=l^2-2l-168[/tex]

This is the area formula. It can be manipulated and solved by completing the square as shown below:

[tex]168+1=l^2-2l +1\\169 = (l+1)^2\\13=(l+1)\\12=l[/tex]

This means the width is w = 12-2 = 10

The length is 12 and the width is 10.

Answer:

L² + 2L - 168 = 0 is the equation that can be used to get the length of the rectangle.

Step-by-step explanation:

Let the length of the rectangle is L and width is W.

Now rectangle's length is 2 meters shorter than its length.

So the equation will be

L = W - 2------(1)

Area of the rectangle is 168 meters²

A = Length × Width

168 = L× W

168 = L× (L + 2) [ From equation 1]

168 = L² + 2L

L² + 2L - 168 = 0

Therefore, L² + 2L - 168 = 0 is the equation that can be used to find the length of the rectangle.