Answer:
84.87sq ft
Step-by-step explanation:
Let ABC be the triangle and AD be the perpendicular on BC such that BD=DC=7ft.
Now, it is known that [tex]\frac{DC}{AC}=cos60^{0}[/tex]
[tex]AC=\frac{7}{\frac{1}{2}}[/tex]
[tex]AC=7ft[/tex]
Now, in triangle ADC, we have
[tex](AC)^{2}=(AD)^{2}+(DC)^{2}[/tex]
[tex](14)^{2}=(AD)^{2}+(7)^{2}[/tex]
[tex]196-49=(AD)^{2}[/tex]
[tex]AD=12.12ft[/tex]
Now, area of the triangle=[tex]\frac{1}{2}{\times}b{\times}h[/tex]
=[tex]\frac{1}{2}{\times}14{\times}12.12[/tex]
=[tex]84.87sq ft[/tex]
Thus, area of the building is 84.87sq ft.
