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An aluminum tea kettle with mass 1.30 kg and containing 1.80 kg of water is placed on a stove. If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20.0 ∘C to 82.0 ∘C ? Q = __________ J

Respuesta :

PSDHE
Heat must be added to raise the temperature from 20.0 •C to 82 •C is
Q= (4200 x 1.8 + 880 x 1.3) x (82 - 20) = 539648J
Lanuel

The quantity of heat required to raise the temperature is 541,260 Joules.

Given the following data:

  • Initial temperature = 20.0°C
  • Final temperature = 82.0°C
  • Mass of aluminum tea kettle = 1.30 kg
  • Mass of water = 1.80 kg

We know that the specific heat capacity of water and aluminum are 4200 and 900 J/kg°C respectively.

To find how much heat must be added to raise the temperature:

Mathematically, heat capacity or quantity of heat is given by the formula;

[tex]Q = mc\theta[/tex]

Where:

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Substituting into the formula, we have:

[tex]Q = ([1.30(900) + 1.80(4200)])(82 - 20)\\\\Q = (1170 + 7560)(62)\\\\Q = 8730(62)[/tex]

Quantity of heat, Q = 541,260 Joules

Therefore, the quantity of heat required to raise the temperature is 541,260 Joules.

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