Find the vertex of the parabola y=x^2 — 2x + 3/10

Answer:
The vertex would be (1, -7/10)
Step-by-step explanation:
In order to find the vertex, start by finding the x-coordinate. The x-coordinate can be calculated using -b/2a, in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(-2)/2(1)
2/2
1
Now that we know the value of the x-coordinate as 1, we can use it in the equation to find y.
y = x^2 - 2x + 3/10
y = (1)^2 - 2(1) + 3/10
y = 1 - 2 + 3/10
y = -7/10