The coordinates of the vertices of a rectangle are (-8,2),(0,4),(1,0), and (-7,-2)
What is the perimeter of the rectangle? Round each step to the nearest tenth.
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SerenaBochenek SerenaBochenek · Answer 1 · 2019-02-01T06:42:13+01:00

Answer:

Perimeter of rectangle is 24.74 squnits.

Step-by-step explanation:

Given The coordinates of the vertices of a rectangle are (-8,2),(0,4),(1,0), and (-7,-2). we have to find the perimeter of rectangle.

As we know,

Perimeter of rectangle=2(L+B)

Length of rectangle=[tex]\sqrt{(0+8)^2+(4-2)^2}=\sqrt64+4=\sqrt68=2\sqrt17[/tex]

Breadth of rectangle=[tex]\sqrt{(1-0)^2+(0-4)^2}=\sqrt1+16=\sqrt17[/tex]

Now, Perimeter=[tex]2(2\sqrt17+\sqrt17)[/tex]

= [tex]2(3\sqrt17)=6\sqrt17units=24.74 squnits[/tex]

boffeemadrid boffeemadrid · Answer 2 · 2019-02-01T06:57:55+01:00

Answer:

Perimeter of rectangle =24.7 units

Step-by-step explanation:

From the figure, Perimeter of the rectangle=[tex]2(length+breadth)[/tex]

=[tex]2(BC+CD)[/tex]

Now, BC=[tex]\sqrt{(0-1)^{2}+(4-0)^{2}}=\sqrt{1+16}=\sqrt{17}=4.1 units[/tex]

and CD=[tex]\sqrt{(1+7)^{2}+(0+2)^{2}}=\sqrt{64+4}=\sqrt{68}=8.2 units[/tex]

Therefore,perimeter of the rectangle= [tex]2(4.1+8.2)=2(12.3)=24.7 units[/tex].

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