Answer: [tex]\bold{(B)\ a_n=-5(a_{n-1})\quad a_1=9}[/tex]
Step-by-step explanation:
The explicit rule for a geometric sequence is: [tex]a_n=a_1(r)^{n-1}\ \text{where}\ a_1\ \text{is the first term and r is the ratio}[/tex]
The given explicit rule shows that [tex]a_1=9\ \text{and}\ r=-5[/tex]
The recursive rule for a geometric sequence is: [tex]a_n=r(a_{n-1})[/tex]
So, the recursive rule is: [tex]a_n=-5(a_{n-1})[/tex]
