Answer:
hello :
60x² – 155x + 100 = 5 ( 12 x² - 31 x + 20 )
delta of ( 12x² - 31 x + 20 ) is b² - 4ac when : a = 12 b = -31 c = 20
delta = ( - 31 )² - 4(12)(20) = 961 - 960 = 1
x1 = (31-1)/24 = 30/24 = 5/4
x2 = (31+1)/24 = 32/24 = 4/3
Factor 60x2 – 155x + 100 = 5 (12(x -5/4)(x- 4/3)) = 60 (x -5/4)(x- 4/3)
Answer:
The factor of the provided expression is [tex]5[\left(4x-5\right)\left(3x-4\right)][/tex].
Step-by-step explanation:
Consider the provided expression.
[tex]60x^2-155x+100[/tex]
Factor out common term 5.
[tex]5(12x^2-31x+20)[/tex]
[tex]5(12x^2-15x-16x+20)[/tex]
[tex]5[\left(12x^2-15x\right)+\left(-16x+20\right)][/tex]
[tex]5[3x\left(4x-5\right)-4\left(4x-5\right)][/tex]
[tex]5[\left(4x-5\right)\left(3x-4\right)][/tex]
Hence, the factor of the provided expression is [tex]5[\left(4x-5\right)\left(3x-4\right)][/tex].
