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What are the solutions of the equation?

x^2+4x=21

a. 23, -27
b. 3, -7
c. -3, 7
d. 4.8, -4.8

Respuesta :

Answer:

Option (b) is correct.

The solution of the quadratic equation [tex]x^2+4x=21[/tex]  is -7 and 3

Step-by-step explanation:

Consider the given quadratic equation [tex]x^2+4x=21[/tex]

This can be rewritten as, [tex]x^2+4x-21=0[/tex]

We can solve the quadratic equation using middle term splitting method,

4x can be written as 7x-3x , we get,

[tex]\Rightarrow x^2+4x-21=0[/tex]

[tex]\Rightarrow x^2+7x-3x-21=0[/tex]

Taking terms common, we get,

[tex]\Rightarrow  x(x+7)-3(x+7)=0[/tex]

Thus, [tex]\Rightarrow (x-3)(x+7)=0[/tex]

Thus, we get (x-3)= 0 or (x+7)= 0  

this gives x = 3 or x = -7

Thus, the solution of the quadratic equation [tex]x^2+4x=21[/tex]  is -7 and 3