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The rectangle shown has a perimeter of 80 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Respuesta :

Answer:  Dimensions of rectangle are 12 cm and 28 cm .

Step-by-step explanation:

Since we have given that

Perimeter of rectangle = 80 cm

Let the length of rectangle be x

Let the width of rectangle would given by

[tex]2x+4[/tex]

According to question,

[tex]\text{Perimeter of rectangle}=2(L+B)\\\\80=2(x+2x+4)\\\\\frac{80}{2}=3x+4\\\\40=3x+4\\\\40-4=3x\\\\36=3x\\\\x=\frac{36}{3}\\\\x=12\ cm[/tex]

Hence, Length of rectangle is 12 cm

Width of rectangle be

[tex]2x+4=2\times 12+4\\\\24+4=28\ cm[/tex]

Therefore, Dimensions of rectangle are 12 cm and 28 cm .

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