Answer:
Area of the bookmar = 68.56 sq.cm.
Step-by-step explanation:
It is given that the diameter of each circle is the width of the rectangle.
Therefore, each radius = [tex]\frac{4}{2}[/tex] = 2 cm.
Area of the 2 semi circles = 2 × 0.5 × 3.14 × [tex]2^{2}[/tex]
= 4 × 3.14
= 12.56 sq.cm.
Now, area of the rectangle = length × width
= 14 × 4
= 56 sq.cm
Area of the bookmark = Area of the rectangular part + 2 × (area of the semicircular part)
= 56 + 12.56
= 68.56 sq.cm.
