Respuesta :

Hello from MrBillDoesMath!

Answer:

Yes!


Discussion:

a + b= 2a                =>  subtract "a" from both sides

a - a + b = 2a - a    =>  as (a-a) = 0 and (2a-a) = a

b = a                      (*)

Then  from (*) above

      b-a = b - b       => b-b = 0

      b -a = 0



Thank you,

MrB