Answer: A) [tex](0,900)\ and\ (3,1500)[/tex]
B) Slope=200, It means enrollment of 200 students increases each year.
C) [tex]P=200t+900[/tex]
D) 2500 students.
Step-by-step explanation:
Given: The student enrollment of the high school, P, has increased at a constant rate each year, t, since 2009.
At 2009, t=0 and at 2012, t=3 [Since 2012-2009=3 years]
A) In points , the given enrollment numbers will be written as:-
[tex](0,900)\ and\ (3,1500)[/tex]
B) The slope of the line passing through [tex](0,900)\ and\ (3,1500)[/tex] is given by:-
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1500-900}{3-0}=\frac{600}{3}=200[/tex]
It means enrollment of 200 students increases each year.
C) The linear equation with slope= 200 and and the initial number of students (900) is given by
[tex]P=200t+900[/tex]
D) At 2017, t=8 [Since 2017-2009=8]
Then [tex]P=200(8)+900=1600+900=2500[/tex]
The high school's enrollment in 2017 = 2500 students.