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A 341.3 Hz tuning fork is resonating in a closed tube on a cool day. If the tube has a length of 0.24 m, then what is the speed of sound in this experiment?


A) 328 m/s


B) 340 m/s


C) 343 m/s


D) There is not enough information to tell.

Respuesta :

f = frequency of tuning fork = 341.3 Hz

L = length of the tube in the experiment = 0.24 m

v = speed of the sound used in the experiment = ?

fundamental frequency in closed tube is given as

[tex]f=\frac{v}{4L}[/tex]

inserting the values

[tex]341.3 =\frac{v}{4(0.24)}[/tex]

v = 4 (341.3) (0.24)

v = 327.65 [tex]\frac{m}{s}[/tex]

hence the correct choice comes out to be A) 328 m/s


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