Answer:
Option c
Step-by-step explanation:
Given the particulars about number of books read by males and females in a high school in the past year.
Males had a mean of 8.4 with std dev 2.3
Females had a mean of 5.9 and std dev 1.8
Sample size was 107 for males and 120 for females
Mean difference between boys and girls = 8.4-5.9 = 2.5
Std error for difference =0.260
For 95% confidence interval
Margin of error =1.96(STd error)
= 1.96(0.260)
=0.51
Hence confidence interval for difference of means Males - Mean females
= (1.99,3.01)
Since mean difference is positive males read more books than females
There is a 95% probability that males seniors at this high school read between 1.99 and 3.01 more books than females
