Respuesta :
Answer: The number of excess electrons that the drop contains are 3.
Explanation:
We are given:
Charge on millikan's oil drops = [tex]4.8\times 10^{-19}C[/tex]
To calculate the number of excess electrons, we divide the charge on millikan's oil drop by the change on 1 electron.
[tex]\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}[/tex]
We know that:
Charge on 1 electron = [tex]1.60\times 10^{-19}C[/tex]
Putting values in above equation, we get:
[tex]\text{Excess electrons}=\frac{4.8\times 10^{-19}C}{1.60\times 10^{-19}C}\\\\\text{Excess electrons}=3[/tex]
Hence, the number of excess electrons that the drop contains are 3.
