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Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g) −→ co2(g) 2 so2(g). if 0.91 mol of cs2 is combined with 1.52 mol of o2, identify the limiting reactant.

Respuesta :

Answer: Oxygen is the limiting reagent.

Explanation: [tex]CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)[/tex]

As can be seen from the given balanced equation:

3 moles of [tex]O_2[/tex] reacts with 1 mole of [tex]CS_2[/tex]

1.52 moles of [tex]O_2[/tex] reacts with=[tex]\frac{1}{3}\times 1.52=0.51moles[/tex] of [tex]CS_2[/tex]

Thus [tex]O_2[/tex] is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of [tex]CS_2[/tex] will remain as such and thus  [tex]CS_2[/tex] is an excess reagent.

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