For this case, we must simplify the following expression:
[tex]2 \sqrt {27} + \sqrt {12} -3 \sqrt {3} -2 \sqrt {12}[/tex]
Then, rewriting terms:
[tex]2 \sqrt {27} = 2 \sqrt {9 * 3} = 2 \sqrt {3 ^ 2 * 3} = 6 \sqrt {3}\\\sqrt {12} = \sqrt {3 * 4} = \sqrt {2 ^ 2 * 3} = 2 \sqrt {3}\\2 \sqrt {12} = 2 \sqrt {3 * 4} = 2 \sqrt {2 ^ 2 * 3} = 4 \sqrt {3}[/tex]
Rewriting the expression:
[tex]6 \sqrt {3} +2 \sqrt {3} -3 \sqrt {3} -4 \sqrt {3} = \sqrt {3}[/tex]
Answer:
[tex]\sqrt {3}[/tex]
