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randall wants to mix 32 lb of nuts worth $2 per lb with some nuts worth $6 per lb to make a mixture worth $5 per lb. how many pounds of $6 nuts must use

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JeanaShupp

Answer: 96 pounds


Step-by-step explanation:

Let x be the number of pounds of $6 nut required .

then you know the weight of the resulting mixture = (x+32)

The total cost of the mixture= [tex]5(x+32)[/tex]

According to the question,

[tex]5(x+32)=32\times2+6x\\\Rightarrow\ 5x+160=64+6x\\\Rightarrow\ 6x-5x=160-64\\\Rightarrow\ x=96[/tex]

Hence, Randall must use 96 pounds of $6 nuts.


lublana

Answer:

96 lb

Step-by-step explanation:

We are given that

Number of nuts =32 lb

Cost of 1 nut=$2

We have to find that how many pounds of $6 nuts must used.

Let x pounds be the nuts worth $6 per lb must be used.

Mixture =32+x

Cost of one lb nut in mixture =$5

According to question

[tex]32(2)+x(6)=(32+x)\times 5[/tex]

[tex]64+6x=160+5x[/tex]

[tex]6x-5x=160-64[/tex]

[tex]x=96[/tex]

Hence, 96 lb of nuts worth $6 per lb must used.

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