Answer: 166.13 kcal
Explanation:
1 ounce = 28.35 g
0.440 ounce=[tex]\frac{28.35}{1}\times 0.440=12.47g[/tex]
Given: 45.0 g of methane releases= 2498 kJ of heat energy
Thus 12.47 g of methane releases=[tex]frac {2498}{45}\times 12.47=692.2kJ[/tex] of heat energy
1 kJ =0.24 kcal
692.2 kJ=[tex]\frac {0.24}{1}\times 692.2=166.13kcal[/tex]
