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To approach the runway, a pilot of a small plane must begin a 10° 10° {"version":"1.1","math":"10°"}  descent starting from a height of 1983 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?

Respuesta :

Answer:

2.1258 miles from the runway is the airplane at the start of this approach

Step-by-step explanation:

ΔABC

AB = 1,983 feets

[tex]\tan\alpha =\frac{AB}{AC}[/tex]

[tex]\tan10^o=0.1763=\frac{1,983}{AC}[/tex]

[tex]AC=\frac{1,983}{0.1763}=11,247.87 feets[/tex]

1 foot = 0.000189 mile

1,247.87 feets = 1,247.87 × 0.000189 mile = 2.1258 miles

2.1258 miles from the runway is the airplane at the start of this approach

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