Answer:
The answer is (0,1) and (3,27)
Step-by-step explanation:
Given points (0,1)(1,3)(2,6)(3,27)
and equation of line y=3x .........[1]
The points that will satisfy the equation lie on it
Taking (0,1) : Putting it in [1] It does not satisfy it as 3*0=0
Taking (1,3): When we put it in [1] 1*3=3
i.e. it satisfy the equation
Taking (2,6): When we put it in [1] 2*3=6
i,e, it satisfy the equation
Taking (3,27): On putting it in [1] 3*3= 9
i.e. it does not satisfy the equation
Hence (0,1) (3,27) does not lie on y=3x
Answer:
Point (0,1) and (3,27) does not lies on the graph y = 3x
Step-by-step explanation:
Consider the given graph of y = 3x
We have to check out of given points (0, 1) (1, 3) (2, 6) (3, 27) lies on the graph y= 3x.
We put x values in equation of given graph y = 3x and see if we get the y values.
1) (0, 1)
Graph equation x = 0 then 3(0)= 0 ≠ 1
Thus, point (0, 1) does not lies on the graph y = 3x
2) (1, 3)
Graph equation x = 1 then 3(1) = 3 = y
Thus, point (1, 3) lies on the graph y = 3x.
3) (2, 6)
Graph equation x = 2 then 3(2)= 6 = y
Thus, point (2, 6) lies on the graph y = 3x.
4) (3, 27)
Graph equation x = 3 then 3(3)= 9 ≠ 27
Thus, point (3,27) does not lies on the graph y = 3x
We can also check by seeing the graph of y = 3x (attached below)
Thus, Point (0,1) and (3,27) does not lies on the graph y = 3x
