Respuesta :

Answer:

Option D is correct.

x             y

0             5

1              10

2              20

Step-by-step explanation:

Given the equation:  [tex]y = 5(2)^x[/tex]           .....[1]

Here, x is the input variable and y is the output variable.

For x =0

Substitute in equation [1]; we have;

[tex]y = 5(2)^{0} = 5 \cdot 1= 5[/tex]

For x = 1

Substitute in equation [1]; we have;

[tex]y = 5(2)^{1} = 5 \cdot 2= 10[/tex]

For x =2

Substitute in equation [1]; we have;

[tex]y = 5(2)^{2} = 5 \cdot 4= 20[/tex]

Therefore, the table values which is correct for the equation [tex]y = 5(2)^x[/tex]  is;

x             y

0             5

1              10

2              20