All the slope of quadrilateral ABCD calculated by using formula of slope.
Given:
A quadrilateral ABCD with vertices A(–4, –5), B(–3, 0), C(0, 2), and D(5, 1).
We have to calculate the slope of AB, DC, BC, AD.
By using formula of slope,
[tex]Slope=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Now, calculate the slope of AB,
A(–4, –5), B(–3, 0), put this value in (1)
[tex]Slope=\dfrac{0-(-5)}{-3-(-4)}= \dfrac{5}{1} =5[/tex]
Calculate the slope of DC,
C(0, 2), D(5, 1), put this value in (1)
[tex]Slope=\dfrac{2-1}{0-5}= \dfrac{-1}{5}[/tex]
Calculate the slope of BC,
B(–3, 0), C(0, 2), put this value in (1)
[tex]Slope=\dfrac{2-0}{0-(-3)}= \dfrac{2}{3}[/tex]
Calculate the slope of AD,
A(–4, –5), D(5, 1), put this value in (1)
[tex]Slope=\dfrac{1-(-5)}{5-(-4)}= \dfrac{6}{9}= \dfrac{2}{3}[/tex]
For further details, please prefer this link:
https://brainly.com/question/18171816
Answer:
step 1= 5
step 2= -1/5
step 3= 2/3
step 4= 2/3
-only one pair of opposite sides is parallel
Step-by-step explanation:
got it right on ed. ;p
