Answer:
F' = 875 N
Explanation:
It is given that,
Mass of the person, m = 70 kg
Acceleration of the elevator, [tex]a=2.5\ m/s^2[/tex] (accelerating upward)
We need to find the force of the elevator on the person. When the elevator is moving upward the force acting on it is given by :
[tex]F'=ma+mg[/tex]
g is the acceleration due to gravity
[tex]F'=m(a+g)[/tex]
[tex]F'=70\times (2.5+10)[/tex]
F' = 875 N
So, the force of the elevator on the person is 875 N. Hence, this is the required solution.
