Respuesta :

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

[tex]\mu=84[/tex]

a standard deviation of 5

so,

[tex]\sigma=5[/tex]

we have

x=89

now, we can use z-score formula

[tex]z=\frac{x-\mu}{\sigma}[/tex]

now, we can plug values

[tex]z=\frac{89-84}{5}[/tex]

[tex]z=1[/tex]

now, we can use calculator

and we get

[tex]p(z>1)=0.1587[/tex]

So,

The percentage of the students scored higher than 89% is 15.87%

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