The width of a rectangle is 3 feet shorter than its length. The perimeter is 530 feet. Let x equal the length of the rectangle. The formula is P = 2l + 2w. What are the length and the width of the rectangle? a. Write a list of the known information and the unknown information. Write an algebraic equation to show the relationship between the knowns and the unknowns. Solve the equation.

Respuesta :

Answer:

1) Known information:

- The perimeter.

- [tex]width=lenght-3ft[/tex]

- The formula of the perimeter of the rectangle:

[tex]P=2l+2w[/tex]

Unknown information:

- The value of the widht.

- The value of the length.

2) Equation:

[tex]530=2l+2w\\530=2l+2(l-3)[/tex]

3) [tex]l=134\\w=131[/tex]

Step-by-step explanation:

1. The problem gives you the perimeter, the formula of the perimeter of a rectangle and says that the width of a rectangle is 3 feet shorter than its length ([tex]w=l-3[/tex]), but does not give the value of the widht and the value of the lenght.

2. Based on the information given, you can write the following equation:

[tex]530=2l+2w[/tex]

Where [tex]l[/tex] is the lenght and [tex]w[/tex] is the width.

Substitute [tex]w=l-3[/tex] into the equation above, then you have:

 [tex]530=2l+2(l-3)[/tex]

3. Solve for the lenght:

[tex]530=2l+2(l-3)\\530=2l+2l-6\\536=4l\\l=134[/tex]

4. Know you can calculate the width:

[tex]w=l-3=134-3=131[/tex]

5. Therefore, the length is 134 feet and the widht is 131 feet.

Otras preguntas