Answer:
Graph has been shown in the attached file.
Step-by-step explanation:
We have been given the system of equations
[tex]4x+4y=16.......(1)\\x+6y=-6.........(2)[/tex]
Both the equation represents a straight lines. We can find the x and y intercepts of these lines to graph.
The intercept form of a line is given by
[tex]\frac{x}{a}+\frac{y}{b}=1[/tex]
Here a is the x - intercept and b is the y-intercept.
Divide both sides of the equation (1) by 16
[tex]\frac{4x}{16}+\frac{4y}{16}=1\\\\\frac{x}{4}+\frac{y}{4}=1[/tex]
Hence, x-intercept = 4 and the point is (4,0)
y-intercept = 4 and the point is (0,4)
Similarly, for the second line
Divide both sides of the equation (2) by -6
[tex]\frac{x}{-6}+\frac{6y}{-6}=1\\\\\frac{x}{-6}+\frac{y}{-1}=1[/tex]
x-intercept = -6 and the point is (-6,0)
y-intercept = -1 and the point is (0,-1)
We'll plot these points in the xy- plane and then join to get the graph of these lines.
