The final temperature will be "47.65°C"
Given values are:
- Heat, Q = 125 cal
- Mass, m = 60 g
- Specific heat, S = 0.0920 cal/g
- Temperature, T = (t-25)
As we know,
The amount of heat supplied is:
→ [tex]Q = mSdT[/tex]
By substituting the values, we get
→ [tex]125=60\times 0.0920\times (t-25)[/tex]
→ [tex]125=5.52\times (t-25)[/tex]
→ [tex]\frac{125}{5.52} = t-25[/tex]
→ [tex]22.65=t-25[/tex]
→ [tex]t = 22.65+25[/tex]
→ [tex]=47.65^{\circ} C[/tex] (Final temperature)
Thus the above is the right answer.
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